Python 解析 Spring pom 文件获取 jar 包名称

前段时间在做持续集成有个小需求是根据 pom 文件获取 jar 包名称,在网上搜寻一番,整理了一份脚本,可以直接使用,通过解析 pom 文件获取(xml2pydict.py):
使用示例:python xml2pydict.py pom.xml
输出结果:jar 包名称

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#!/usr/bin/env python
# -*- coding: utf-8 -*-
# @Time : 2018/10/22 下午5:53
# @Author : haohao.qiang
# @Mail : qhh0205@gmail.com
# @File : xml2pydict.py

import sys
import warnings
from xml.parsers import expat
import xml.etree.ElementTree as ElementTree
warnings.filterwarnings("ignore")

class XmlListConfig(list):
def __init__(self, aList):
for element in aList:
if element:
# treat like dict
if len(element) == 1 or element[0].tag != element[1].tag:
self.append(XmlDictConfig(element))
# treat like list
elif element[0].tag == element[1].tag:
self.append(XmlListConfig(element))
elif element.text:
text = element.text.strip()
if text:
self.append(text)


class XmlDictConfig(dict):
'''
Example usage:

tree = ElementTree.parse('your_file.xml')
root = tree.getroot()
xmldict = XmlDictConfig(root)

Or, if you want to use an XML string:

root = ElementTree.XML(xml_string)
xmldict = XmlDictConfig(root)

And then use xmldict for what it is... a dict.
'''
def __init__(self, parent_element):
if parent_element.items():
self.update(dict(parent_element.items()))
for element in parent_element:
if element:
# treat like dict - we assume that if the first two tags
# in a series are different, then they are all different.
if len(element) == 1 or element[0].tag != element[1].tag:
aDict = XmlDictConfig(element)
# treat like list - we assume that if the first two tags
# in a series are the same, then the rest are the same.
else:
# here, we put the list in dictionary; the key is the
# tag name the list elements all share in common, and
# the value is the list itself
aDict = {element[0].tag: XmlListConfig(element)}
# if the tag has attributes, add those to the dict
if element.items():
aDict.update(dict(element.items()))
self.update({element.tag: aDict})
# this assumes that if you've got an attribute in a tag,
# you won't be having any text. This may or may not be a
# good idea -- time will tell. It works for the way we are
# currently doing XML configuration files...
elif element.items():
self.update({element.tag: dict(element.items())})
# finally, if there are no child tags and no attributes, extract
# the text
else:
self.update({element.tag: element.text})


if __name__ == "__main__":
xml = sys.argv[1]
oldcreate = expat.ParserCreate
expat.ParserCreate = lambda encoding, sep: oldcreate(encoding, None)
tree = ElementTree.parse(xml)
root = tree.getroot()
xmldict = XmlDictConfig(root)
print "{}-{}.{}".format(xmldict.get('artifactId'), xmldict.get('version'), xmldict.get('packaging'))